Let
A-----> \(\frac{7}{8}\)
B-----> \(\frac{11}{10}\)
C-----> \(1\)
we know that
Point A-------> Multiply numerator and denominator by \(10\)
\(\frac{7*10}{8*10} =\frac{70}{80}\)
Point B-------> Multiply numerator and denominator by \(8\)
\(\frac{11*8}{10*8} =\frac{88}{80}\)
Point C-------> Multiply numerator and denominator by \(80\)
\(\frac{1*80}{1*80} =\frac{80}{80}\)
Find the distance Point A to Point C
\(\frac{80}{80} -\frac{70}{80} =\frac{10}{80}\)
Find the distance Point B to Point C
\(\frac{88}{80} -\frac{80}{80} =\frac{8}{80}\)
therefore
\(\frac{8}{80} < \frac{10}{80}\)
Point B is closer to Point C
\(\frac{11}{10}\) is closer to \(1\)
the answer is
\(\frac{11}{10}\) is closer to \(1\)
