Graph the line : y= -2/3x+4
x=0 => y =4 => A(0, 4)∈ Gf;x = 1 => y = 10/3 => B(1, 10/3)∈ Gf;Graph tle line AB.
\(y=-\frac{2}{3}x+4\\\\for\ x=0\to y=-\frac{2}{3}\cdot0+4=4\to A(0;\ 4)\\\\for\ x=6\to y=-\frac{2}{ ot3_1}\cdot ot6^2+4=-4+4=0\to B(6;\ 0)\)
