To calculate the speed in the mentioned interval, what we must do is calculate the average rate of change.
By definition, the average rate of change is given by:
\(AVR = \frac{r(t2) - r(t1)}{t2 - t1}\)
Substituting values we have:
\(AVR = \frac{4.2 - 2.8}{0.084 - 0.051}\)
We rewrite:
\(AVR = 42.4 \frac{Km}{h}\)
Answer:
The average speed between 2.8 km and 4.2 km of the bus is:
\(AVR = 42.4 \frac{Km}{h}\)
