Answered

HURRY !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Xander was traveling at a final velocity of 4.5 m/s for 3.5 seconds. Finley was traveling at a final velocity of 3.6 m/s for 4.2 seconds. Max was traveling at a final velocity of 7.3 m/s for 1.2 seconds. They all started from the same location.

Which lists them from least to most acceleration?

AMax → Finley → Xander
BMax → Xander → Finley
CXander → Finley → Max
DFinley → Xander → Max

Verified Answer :

The answer is D. Finley → Xander → Max because Finley was the slowest and xavier was the fastest

Answer:  D. Finley → Xander → Max

Explanation:

Given

Xander , Finley and Max all started from the same location . So all are having initial velocity zero .

Final velocities are

\(V_{xander}=4.5 \frac{m}{s} ,V_{finley}=3.6 \frac{m}{s}, V_{max}=7.3\frac{m}{s}\)

Now , Acceleration , \(a=\frac{V_{final}-V_{initial}}{t}\)

=> Acceleration of Xander , \(a_{xander}=\frac{4.5}{3.5}\frac{m}{s^{2}} = 1.29 \frac{m}{s^{2}}\)

Acceleration of Finley , \(a_{finley}=\frac{3.6}{4.2}\frac{m}{s^{2}} = 0.857 \frac{m}{s^{2}}\)

Acceleration of Max , \(a_{max}=\frac{7.3}{1.2}\frac{m}{s^{2}} = 6.08 \frac{m}{s^{2}}\)

Thus order of their acceleration from least to most is Finley → Xander → Max

=> correct option is D. Finley → Xander → Max

Related Questions