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Find the sine of both angle A and angle B.

Asin A = 5/13; sin B = 12/13
Bsin A = 12/13; sin B = 5/13
Csin A = 5/12; sin B = 12/5
Dsin A = 13/5; sin B = 13/12

Find the sine of both angle A and angle B. A. sin A = 5/13; sin B = 12/13 B. sin A = 12/13; sin B = 5/13 C. sin A = 5/12; sin B = 12/5 D. sin A = 13/5; sin B = class=

Verified Answer :

sin = opposite/hyp

Sin A = 10/26   = 5/13

Sin b = 24/26 = 12/13

The answer is option A

Hope this helps

Answer:

The correct option is A.

Step-by-step explanation:

Let the third vertex of the triangle be C and the angle C is 90 degree.

In a right angles triangle, the sine ratio is defined as

\(\sin \theta=\frac{perpendicular}{hypotenuse}=\frac{opposite}{hypotenuse}\)

Using sine ratio,

\(\sin A=\frac{BC}{AB}\)

\(\sin A=\frac{10}{26}\)

\(\sin A=\frac{5}{13}\)

\(\sin B=\frac{AC}{AB}\)

\(\sin B=\frac{24}{26}\)

\(\sin B=\frac{12}{13}\)

Since \(\sin A=\frac{5}{13}\) and \(\sin B=\frac{12}{13}\), therefore the correct option is A.

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