Mass box a = 10 grams; mass box b = 5 grams; mass box c—made of one a and one b how many grams of a would be needed to give the same number of particles: as 7.5 grams of b? as 2.5 grams? as 12.5 grams? as 1 gram?
Answer:
The correct answers are 15g A, 5g A, 25g A and 2g A.
Explanation:
First we must take into account the masses of A (\(m_{A}\)) and B (
\(m_{B}\)) :
\(m_{A}\) = 10g
\(m_{B}\) = 5g
Now, in the case of 7.5 g of B:
\(m_{A1}\) = (7.5g B / 5g B) 10g A = 15gA
For the case of 2.5 g of B:
\(m_{A2}\) = (2.5g B / 5g B) 10g A = 5gA
For the case of 12.5 g of B:
\(m_{A3}\) = (12.5g B / 5g B) 10g A = 25gA
For the case of 1 g of B:
\(m_{A4}\) = (1g B / 5g B) 10g A = 2gA
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