Answered

  1. A particle is moving along the curve below.

y = 2sin(πx/2)


As the particle passes through the point (1/3,1) its x-coordinate increases at a rate of sqrt(10) cm/s. How fast is the distance from the particle to the origin changing at this instant?

Verified Answer :

syed514

x'=sqrt(10) 

 2r r' = 2x x' + 2y y'

 r' = (2x x' + 2y y')/2r

 r' = (x x' + y y')/r 

 we know x'; and since y is a function of x we can know y' as well


Related Questions