Answered

Find the area of triangle ABC with the given parts. Round to the nearest whole number.


A = 26.4°

b = 12.3 in.

c = 7.7 in.


a- 19.1 in.2

b- 42.4 in.2

c- 44.4 in.2

d- 21.1 in.2

Verified Answer :

\(\sin{26.4^o}= \frac{h}{12.3} \\ \\h=12.3\times \sin{26.4^o}=5.47 \\ \\A= \frac{7.7\times5.47}{2}= 21.06\)

View image alsteva

Related Questions