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Reaction is

CO2(g) + C(s) <=> 2CO(g)

Kp = 5.7, 1200K


Calcualte the total pressure at equilibrium when 4.45g CO2 is introduced into a 10.0L container and heated to 1200K in the presence of 2.00g of graphite

Verified Answer :

antonsandiego

According  to the task, you  are proveded with patial pressure of CO2 and graphite, and here is complete solution for the task :
At first you have to find n1 =moles of CO2 and n2 which are moles of C 
The you go :
\(CO2(g) + C(s) \ \textless \ =\ \textgreater \ 2CO(g)\)

n1 n2 0

-x -x +2x
\(n1-x n2-x 2x Kp=P^2 (CO)/Pco2\)
After that you have to use the formula \(PV=nRT\)
 \(Kp=(2x)^2/n1-x\)
Then you have to solve x, and for that you have to use RT/V
And to find total values:\(P(total)=n(total)*R*T/V\)
I am absolutely sure that this would be helpful for you.

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