The answer is \(\frac{ a^{2} b^{3} }{-4}\)
\(\sqrt[3]{ \frac{ a^{6} b^{9} }{-64} } = \frac{ \sqrt[3]{a^{6} b^{9}} }{ \sqrt[3]{-64} } = \frac{ \sqrt[3]{a^{6}} * \sqrt[3]{ b^{9}} }{ \sqrt[3]{-64}}\)
Since (xᵃ)ᵇ = xᵃ*ᵇ, then:
a⁶ = (a²)³
b⁹ = (b³)³
Also: 64 = 4³
\(\frac{ \sqrt[3]{a^{6}} * \sqrt[3]{ b^{9}} }{ \sqrt[3]{-64}}= \frac{ \sqrt[3]{( a^{2})^{3} }*\sqrt[3]{( b^{3})^{3} } }{\sqrt[3]{( -4)^{3} }} = \frac{ a^{2} * b^{3} }{-4}\)
