Hagrid
Answered

Look at the figure.


Triangle PTS has measure of angle PTS equal to 90 degrees. Ris a point on the hypotenuse SP such that the segment RT is perpendicular to PS. Q is a point outside the triangle on the left of R so that triangle PQR has the measure of angle PQR equal to 90 degrees


Which pair of triangles is similar?

Answer


Triangles PTR and PQR


Triangles RTS and PQR


Triangles PQR and PTS


Triangles SRT and TRP

Look at the figure. Triangle PTS has measure of angle PTS equal to 90 degrees. Ris a point on the hypotenuse SP such that the segment RT is perpendicular to PS. class=

Verified Answer :

Answer:ΔSRT and ΔTRP

Step-by-step explanation:

We are given that R is a point on hypotenuse SP such that the segment RT is perpendicular to PS, therefore, PR=RS as the perpendicular bisector divides the line segment in two equal halves.

Now,

In ΔSRT and ΔTRP,

PR=SR( Since RT is perpendicular bisector, it divides PS in two equal halves)

∠PRT=∠SRT=90° (RT is perpendicular bisector of PS)

RT=RT(Common)

Therefore, by SAS rule of congruency,

ΔSRT ≅ΔTRP

Hence, Option D is correct.

Answer:

Triangle RQS

Step-by-step explanation:

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