Answer:
Radius of the loop, r = 0.12 m
Explanation:
It is given that,
Current flowing in the wire, I = 15 A
Magnetic field at the center of the loop, B = 80 μT = 80 × 10⁻⁶ T
The magnetic field at the center of the circular loop is given by :
\(B=\dfrac{\mu_0I}{2r}\)
R is the radius of loop
\(r=\dfrac{\mu_oI}{2B}\)
\(r=\dfrac{4\times 3.14\times 10^{-7}\times 15}{2\times 80\times 10^{-6}}\)
r = 0.12 m
So, the radius of the loop is 0.12 m
Hence, this is the required solution.
