The equation of state corresponding to 8 gm of Oxygen (O2) is : PV=RT,RT/4,RT/3 or RT/2?

Verified Answer :

In PV = nRT, n is the number of moles. When 8 grams of oxygen are present,
n = 8/32 = 1/4
So PV = RT/4

Answer: Option (b) is the correct answer.

Explanation:

According to ideal gas equation, the product of pressure and volume is equal to the product of universal gas constant and absolute temperature.

Mathematically,      PV = nRT       ........... (1)

where       P = pressure

                V = volume

               n = number of moles

              R = gas constant

              T = temperature

Also, number of moles = \(\frac{mass of atom}{molar mass of the atom}\)

Therefore, number of moles of oxygen atom will be as follows.

    Number of moles = \(\frac{mass of atom}{molar mass of the atom}\)

                                  = \(\frac{8}{32}\)

                                  = \(\frac{1}{4}\)

Thus, putting the value of n into equation (1) as follows.

                                PV = nRT

      or                      PV = \(\frac{1}{4}RT\)