The equation of state corresponding to 8 gm of Oxygen (O2) is : PV=RT,RT/4,RT/3 or RT/2?
In PV = nRT, n is the number of moles. When 8 grams of oxygen are present,
n = 8/32 = 1/4
So PV = RT/4
Answer: Option (b) is the correct answer.
Explanation:
According to ideal gas equation, the product of pressure and volume is equal to the product of universal gas constant and absolute temperature.
Mathematically, PV = nRT ........... (1)
where P = pressure
V = volume
n = number of moles
R = gas constant
T = temperature
Also, number of moles = \(\frac{mass of atom}{molar mass of the atom}\)
Therefore, number of moles of oxygen atom will be as follows.
Number of moles = \(\frac{mass of atom}{molar mass of the atom}\)
= \(\frac{8}{32}\)
= \(\frac{1}{4}\)
Thus, putting the value of n into equation (1) as follows.
PV = nRT
or PV = \(\frac{1}{4}RT\)