Each person in a group of college students was identified by graduating year and asked when he or she preferred taking classes: morning, afternoon, or evening. The results are shown in the table. Find the probability that the student preferred morning classes given he or she is a junior. Round to the nearest thousandth. Survey of Class Times Freshman Sophomore Junior Senior Morning 20 14 16 17 Afternoon 5 10 2 7 Evening 15 15 8 14

Verified Answer :

Answer:

0.615

Step-by-step explanation:

The frequency table is attached below.

We have to calculate, the probability that the student preferred morning classes given he or she is a junior.

i.e \(P(\text{Morning }|\text{ Junior})\)

We know that,

\(P(A\ |\ B)=\dfrac{P(A\ \cap\ B)}{P(B)}\)

So,

\(P(\text{Morning }|\text{ Junior})=\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}\)

Putting the values from the table,

\(\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}=\dfrac{\frac{16}{143}}{\frac{26}{143}}=\dfrac{16}{26}=0.615\)

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The probability that the student preferred morning classes given he or she is a junior is 0.615.

What is probability?

Probability is the likelihood of an event happening.

  • Probability = number of expected event/number of possible events

The probability that the student preferred morning classes given he or she is a junior is given below as:

\(P(\text{Morning }|\text{ Junior})\)

\(P(\text{Morning }|\text{ Junior})=\dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})} \\\)

Substituting the values from the table;

\(P(\text{Morning }|\text{ Junior}) = \dfrac{P(\text{Morning }\cap \text{ Junior})}{P(\text{Junior})}=\dfrac{\frac{16}{143}}{\frac{26}{143}}=\dfrac{16}{26}=0.615 \\\)

Therefore, the probability that the student preferred morning classes given he or she is a junior is 0.615.

Learn more about probability at: https://brainly.com/question/24756209

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