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Find the real zeros of the trigonometric function on the interval 0 ≤ x < 2π


f(x) = 4 cos^2(x) - 3

Verified Answer :

syed514

4cos2(x)−3=0

or 
4cos2(x)=3

cos(x)= √3/2

π/6, 5π/6,  7π/6,  11π/6



Edufirst

f(x) = 4 [cos (x)]^2 - 3 = 0

4[cos(x)]^2 = 3

cos(x) = √3 / 2

That happens in the first and fourth quadrants, for the angles 30 degrees and 330 degrees.

Answer: x = 30 degrees and x = 330 degrees

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