What is the equation of the line, first written in point-slope form and then written in slope-intercept form?

What is the equation of the line, first written in point-slope form and then written in slope-intercept form? class=

Verified Answer :

Point Slope:
y-12=-3(x-6)

From there you can find the slope intercept form:

y-12=-3x+18
y=-3x+30

Point-slope form is
y - y1 = m(x - x1), where the (x1, y1) is one of the points.

First find the slope, which is change in y over change in x, orĀ 
\(m= \frac{x2-x1}{y2-y1}\)
The example points
(x1, y1) and (x2, y2) are now
( 3, 21 ) and ( 6, 12 ).
\(m= \frac{12-3}{6-21}= \frac{9}{-3} = -3\)


Now plug the slope and one of the points into the formula
\(y - y1 = m(x - x1) \\ y - 12 = -3(x-6) \\\)

To write in slope-intercept form, y = mx + b, simply solve for y.
\(y - 12 = -3x + 2 \\ y = -3x + 30\)