If 4.50 g of (nh4)2so4 is dissolved in enough water to form 250. ml of solution, what is the molarity of the solution?
The molarity of a solution is the number of moles of a substance in one liter of that substance.
The molar mass of ammonium sulfate (NH4)2SO4 is 132.14 grams/mole
Calculate the moles of ammonium sulfate:
(4.50 grams)/(132.14 grams/mole) = 0.0341 moles of ammonium sulfate
convert mL to Liters 250. mL becomes 0.250 liters
Take the number of moles over the number of liters
0.0341 moles / 0.250 liters = 0.136 molar or 0.136M = molarity of the solution
The molarity is the number of moles in one liter of a solution. The molarity of the solution is 0.136 m.
Molarity is the measure of the concentration of any solute in per unit volume of the solution.
\(M = \dfrac{n}{V}\)
the molar mass of \(\rm (NH_4)2SO_4\) is 132.14 g/mol
Calculating the number of moles
\(\rm Number\;of \;moles= \dfrac{mass}{molar\;mass}\\\\\\Number\;of \;moles= \dfrac{4.50 g}{132.14\;g/mol}= 0.0341 \;mol\)
Calculating the molarity
\(\rm M = \dfrac{n}{V}\\\\\\M = \dfrac{0.0341}{0.250}= 0.136\;m\)
Thus, the molarity of the solution is 0.136 m.
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