Answer:
The zeros of the given function is 1 and 3
Step-by-step explanation:
James creates the table shown to represent the function
\(f(x)=x^2-4x+3\)
Table of f(x)
x | f(x)
-1 | 8
0 | 3
1 | 0
2 | -1
3 | 0
4 | 3
5 | 8
Using table we need to find zeros.
Zeros of the function when function value becomes 0 at given value of x.
So, we will see the table value where f(x) becomes 0
In table we can see f(x) is zero at two value of x
At x=1, f(1)=0
At x=3, f(3)=0
Here we have two zeros at x=1 and 3
Zero: x=1 and x=3
Hence, The zeros of the given function is 1 and 3
