Answered

What are the solutions of 2x2 + 16x + 34 = 0?



–8 ± 2i


–8 ± i


–4 ± 2i


–4 ± i

Verified Answer :

nobillionaireNobley

2x^2 + 16x + 34 = 0
x^2 + 8x + 17 = 0
x^2 + 8x + 16 = -17 + 16 = -1
(x + 4)^2 = -1
x + 4 = sqrt(-1) = ±i
x = -4 ± i

Answer:

\(\text{The solution is }x=-4\pm i\)

Step-by-step explanation:

Given the equation

\(2x^2+16x+34=0\)

we have to find the solutions of above equation

\(2x^2+16x+34=0\)

Comparing it with standard quadratic equation \(ax^2+bx+c=0\)

a=2, b=16, c=34

The solution is

\(x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\)

\(x=\frac{-16\pm \sqrt{16^2-4(2)(34)}}{2(2)}\)

\(x=\frac{-16\pm \sqrt{-16}}{4}\)

\(x=-4\pm i\)

\(\text{The solution is }x=-4\pm i\)

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