Bones23
Answered

Two mechanics worked on a car. The first mechanic worked for

20

hours, and the second mechanic worked for

15

hours. Together they charged a total of

$2000

. What was the rate charged per hour by each mechanic if the sum of the two rates was

$115

per hour?

what is the first mechanics $ per hour? and what was the second mechanics $ per hour?

Verified Answer :

20x + 15y = 2000
x + y = 115
55+60=115

20 (55) + 15 (60)=2000
1100+900=2000
2000=2000

apologiabiology

x=price per hour for first mechanic


y=price per hour for second mechanic




20x+15y=2000


x+y=115


solve


divide first equation by 5


4x+3y=400




multiply second equation by -3 and add
to second



4x+3y=400
-3x-3y=-345 +
1x+0y=55

x=55




x+y=115


55+y=115


minus 55


y=60




first mechanic rage is $55 per hour


second mechanic is $60 per hour



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