If the integral of f(x)dx = 2.3 from 1 to 3 and F'(x) = f(x), what is the value of F(3) - F(0). The graph will be inserted as a picture. ...?
i think you forgot to add the attachment. But I did some research. The correct answer to this question is 2.3 + 1 = 3.3. To solve this, If f(x)dx = 2.3 and F' (x) = f(x),
F(3) − F(0) = 30f(x)dx
2.3 + 1 = 3.3. This is the value of F(3) - F(0).
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