Answer:\(510. 12 cm^3\)
The volume of a cylindrical conduit, \(V=\pi (r_2^2-r_1^2) h\)
where \(r_1\) is the inner radius, \(r_2\) is the outer radius, h is the length.
First of all, we would covert each parameter into centimeters.
length of the conduit, \(h=4 ft=4\times 30.48 cm=121.92 cm\)
outer radius, \(r_1=2.2/2 in =1.1 in= 1.1\times 2.54 cm=2.79 cm\)
inner radius, \(r_1=2/2 in =1 in= 2.54 cm\)
Insert the values in the volume formula,
\(V=3.14 \times (2.79^2-2.54^2) \times 121.92 cm^3=510. 12 cm^3\)
Hence, the volume of metal in the conduit is 510. 12 cubic centimeters.