ayah1
Answered

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  1. A gas occupies 30 L at 760 mm Hg. What is its volume at 350 mm Hg?

P1V1 = P2V2


760 mm Hg 30 L = 350 mm Hg V2


V2 = 22800 mm HgL/350 mm Hg


V2 = about 65.14 L


  1. A gas occupies 500 mL at 1 atm. What is its pressure if the volume becomes 1500 mL?

P1V1 = P2V2


1 atm
500 mL = P21500 mL


500 atm
mL/1500 mL = P2


P2 = 1/3 atm


  1. If a gas occupies 250 mL at 25°C, what will its volume be at 57°C?

25°C + 273 = 298°K; 57°C + 273 = 330°K


V1/T1 = V2/T2


250 mL/298°K = V2/330°K


0.84 mL/k330°K = V2


V2 = about 276.85 mL

  1. What was the original temperature of a 2 L sample of gas if it initially had the volume 5 L at 27°C?

27°C + 273 = 298°K


V1/T1 = V2/T2


5 L/298°K = 2 L/T2


2 L/(0.017 L/K)= T2


T2 = 119.2°K = -153.8°C

  1. At what pressure would 100 mL of a gas be found if it began at 500 mL at 2.5 atm?

P1V1 = P2V2


2.5 atm
500 mL = P2100 mL


125 atm
mL/100 mL = P2


P2 = 1.25 atm

  1. What is the volume of a gas at 275 mm Hg if it occupied 750 mL at 1000 mm Hg?

P1V1 = P2V2


1000 mm Hg750 mL = 275 mm HgV2


750000 mm HgmL/275 mm Hg = V2


V2 = about 2727. 27 mL

  1. A gas occupies 60 L at 250°K and 1 atm. What is its volume at 250°C and 1.5 atm?

250°C + 273 = 523°K


P1
V1/T1 = P2V2/T2


1 atm
60 L/250°K = 1.5 atmV2/523°K


0.24 (atm
L/K)523°K = 1.5 atmV2


125.52 (atmL)/1.5 atm = V2


V2 = 83.68 L

  1. What is the final temperature in Celsius of a gas occupying 3.25 L at 750 mm Hg if it occupied 2250 mL at 37°C and 600 mm Hg?

37°C + 273 = 310°K; 2250 mL = 2.25 L


P1
V1/T1 = P2V2/T2


600 mm Hg
2.25 L/310°K = 750 mm Hg3.25 L/T2


2437.35 mm Hg
L/ (4.35 mm Hg*L/K) = T2


T2 = 559.69°K

T2 = about 286.69°C

Verified Answer :

I saw a slight error in number 8. 750*3.25=2437.5 not 2437.35. That threw your final answer off by a little more than half a °C. Other than that, I didn't see anything wrong.