the sum of the interior angles of a polygon is 540. determine and state the number of degrees in one interior angle of the polygon.
Any polygon with interior angles that add up to 540 must have 5 sides and 5 corners (a pentagon). Assuming it is a regular pentagon, you need to work out what 1/5 of 540 is, which is the same as dividing it by 5. 540/5 = 108. this is the number of degrees in one interior angle of a regular pentagon.
The number of degrees in one interior angle of the polygon is 108 degrees.
A polygon is a closed two-dimensional shape having straight line segments. It is not a three-dimensional shape.
Sum of interior angles of a polygon with n sides IS;
\(\rm (n-2)\times 180\)
Sum of interior angles of a polygon = 540°
Equating both we can determine the number of sides
\(\rm (n-2)\times 180=540\\\ -2=\dfrac{540}{180}\\\\ n-2=3\\\ =3+2\\\ =5\)
There are 5 sides in the polygon and the sum of the interior angles of a polygon is 540.
The number of degrees in one interior angle of the polygon is;
\(=\dfrac{540}{5}\\\\=108\)
Hence, the number of degrees in one interior angle of the polygon is 108 degrees.
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