Verified Answer :

\(S=2(lw+lh+wh)\\ S=2lw+2lh+2wh\\ S=w(2l+2h)+2lh\\ w(2l+2h)=S-2lh\\ w=\frac{S-2lh}{2l+2h}\)

we have

\(s=2(lw+lh+wh)\)

Solve for w means that clear variable w

\(s=2(lw+lh+wh)\\s=2lw+2lh+2wh\)

Group terms that contain the variable w, and move the other terms to the opposite side of the equation

\((s-2lh)=(2lw+2wh)\)

Factor the variable w

\((s-2lh)=w(2l+2h)\)

Divide both sides by \((2l+2h)\)

\((s-2lh)/(2l+2h)=w(2l+2h)/(2l+2h)\)

\(w=(s-2lh)/(2l+2h)\)

therefore

the answer is

\(w=(s-2lh)/(2l+2h)\)