Zoey1999
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A football player weighed 170 2/3 pounds in May. During the summer, he gained 25 5/12 pounds. During the first week of fall practice, he lost 10 1/4 pounds, and during the second week he lost another 3 1/2 pounds. How much did he weigh at that point?


A: 182 1/3 lb

B: 181 1/2 lb

C: 182 5/12 lb

D: 183 2/3 lb


Help please?

A football player weighed 170 2/3 pounds in May. During the summer, he gained 25 5/12 pounds. During the first week of fall practice, he lost 10 1/4 pounds, and class=

Verified Answer :

Answer:

182 1/3 lbs

MAY:  weight = 170 2/3

Summer: gained 25 5/12

New weight : 170 2/3 + 25 5/12  

Get a common denominator of 12

170 2/3 4/4  + 25 5/12

170 8/12 + 25 5/12 = 195 13/12

The he lost 10 1/4 during the first week of fall practice

195 13/12 - 10 1/4

We need to get a common denominator of 12

195 13/12 - 10 1/43/3

195 13/12 - 10 3/12

185 10/12

The he lost another 3 1/2 pound during the second week

185 10/12 - 3 1/2

We need to get a common denominator of 12

185 10/12 - 3 1/2 * 6/6

185 10/12 - 3 6/12

182 4/12

Simplify the fraction

182 1/3 lbs

Hope this helps!

have a great day! :))))))

boffeemadrid

We need to find the weight of a person at a certain period of time.

The weight of the person at the required time is A. \(182\dfrac{1}{3}\ \text{lb}\)

Initial weight of person = \(170\dfrac{2}{3}\) pounds.

Weight gained = \(25\dfrac{5}{12}\) pounds

Weight lost = \(10\dfrac{1}{4}+3\dfrac{1}{2}\) pounds

So, weight of the person is

\(170\dfrac{2}{3}+25\dfrac{5}{12}-(10\dfrac{1}{4}+3\dfrac{1}{2})\\ =170+\dfrac{2}{3}+25+\dfrac{5}{12}-(10+\dfrac{1}{4}+3+\dfrac{1}{2})\\ =195+\dfrac{8+5}{12}-13-\dfrac{1+2}{4}\\ =182+\dfrac{13}{12}-\dfrac{3}{4}\\ =182+\dfrac{13-3}{12}\\ =182+\dfrac{10}{12}\\ =182+\dfrac{1}{3}=182\dfrac{1}{3}\)

The weight of the person at the required time is A. \(182\dfrac{1}{3}\ \text{lb}\)

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