Verified Answer :

apologiabiology
  1. so since we assume that CF is a straight line that means that the angle CAF is 180 angle CAD is 90 and FAE is 65 so 180-(65+90)=DAE=25

    2. so since angle QPR= angle TPS (both are signified by f) and we assume that QT is straight so then QPT=180
    180-154=2f=26
    angle f=13
    QPR=13

    3. so we assume that BG is straight so it is 180
    we add up the known angles (BQD+DQE+FQG=10+103+12=125) 180-125=DQC+EQF=55=2x+3x=5x
    5x=55
    x=11
    CQD=2x=22
    EQF=3x=33

    4. we know that x=x and the whole is 360 so
    x+x+x+x+71+71+71+71=360=4x+284=360
    4x=76
    x=19

    8. so we assume that EF and CD are straight lines so EQD=CQF so 155=56+3x so
    99=3x
    CQG=99

    9. so adjacent and the ratio is 4:5 so a line is 180 so 4+5=9 180/9=20  204=80 205=100 4:5 =80:100

    a. 80 and 100
    b. you should be able to do this

    10. so on a line is 180
    a. 3:4:5  3+4+5=12  180/12=15
    315=45  415=60  5*15=75
    3:4:5 =45:60:75
    the angles are 45 60 75

    b. you should be able to do this from my work

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