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\(\rho=0,93\frac{g}{mL}\\ m_{r}=285g\\\\ \rho=\frac{m_{r}}{V_{r}} \ \ \ \ \ \Rightarrow \ \ \ \ \ \ \ \ V_{r}=\frac{m_{r}}{\rho}\\\\ V_{r}=\frac{285g}{0,93\frac{g}{mL}}\approx306mL\approx0,306L\)

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