Answered

Sue took her collection of nickels and dimes to deposit it in the bank. She has five fewer nickels than dimes. Her total deposit was $66.80 How many dimes

did she deposit?

Verified Answer :

.05N+.10D=66.80
D-N=5  --> D=5+N
Substitute
.05N+.10(5+N)=66.80
.05N+.50+.10N=66.80
.15N=66.30
Nickles=442
D-N=5
D-442=5
Dimes=447
Check
.05N+.10D=66.80
.05(442)+.10(447)=66.80
22.10+44.70=66.80
66.80=66.80
442 Nickles and 447 Dimes

Sue deposited 447 dimes and 442 nickels if Sue took her collection of nickels and dimes to deposit in the bank. She has five fewer nickels than dimes.

What is a linear equation?

It is defined as the relation between two variables, if we plot the graph of the linear equation we will get a straight line.

If in the linear equation, one variable is present, then the equation is known as the linear equation in one variable.

It is given that:

Sue took her collection of nickels and dimes to deposit it in the bank. She has five fewer nickels than dimes.

Her total deposit was $66.80.

Let N and D are the nickels and dimes.

From the question:

D - 5 = N

0.10D + 0.05N = 66.80  (after converting nickels and dimes to dolllars)

Plug D = N + 5 in the second equation:

0.05N +0.10(5 + N) = 66.80

After solving:

0.05N + 0.50 + 0.10N = 66.80

N = 442

D = 447

Thus, Sue deposited 447 dimes and 442 nickels if Sue took her collection of nickels and dimes to deposit in the bank. She has five fewer nickels than dimes.

Learn more about the linear equation here:

brainly.com/question/11897796

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