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crisdiaz1 crisdiaz1
  • 06-12-2014
  • Mathematics
Answered

x=6y+30

x=3/2y

solve by substitution.

Verified Answer :

naǫ
naǫ naǫ
  • 06-12-2014

\(x=6y+30 \\ x=\frac{3}{2}y \\ \\ \hbox{substitute } \frac{3}{2}y \hbox{ for x in the 1st equation:} \\ \frac{3}{2}y=6y+30 \\ \frac{3}{2}y-6y=30 \\ 3y-12y=60 \\ -9y=60 \\ y=-\frac{60}{9}=-\frac{20}{3}=-6\frac{2}{3} \\ \\ x=\frac{3}{2} \cdot (-\frac{20}{3})=-\frac{20}{2}=-10 \\ \\ \left \{ {{x=-10} \atop {y=-6\frac{2}{3}}} \right.\)

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