taylorbonham251 taylorbonham251

03-12-2014
Mathematics

Answered

how do you solve polynomial equation by factoring

2x^3 - 12x^2 = 32x - 192

Verified Answer :

konrad509 konrad509

03-12-2014

\(2x^3 - 12x^2 = 32x - 192\\ 2x^3-12x^2-32x+192=0\\ 2(x^3-6x^2-16x+96)=0\\ 2(x^2(x-6)-16(x-6))=0\\ 2(x^2-16)(x-6)=0\\ 2(x-4)(x+4)(x-6)=0\\ x=4 \vee x=-4 \vee x=6\)

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