Find two consecutive numbers whose sum is 117
\(n+n+1=117\\ 2n=116\\ n=58\\ n+1=59\)These numbers are 58 and 59.
So,x + y = 117y = x + 1x + x + 1 = 117Collect Like Terms2x + 1 = 117Subtract 1 from both sides2x = 116Divide both sides by 2x = 58y = x + 1y = 58 + 1y = 59The 2 consecutive integers are 58 and 59.
