The four consecutive even integers will be expressed as
\(n \\ n+2 \\ n+4 \\ n+6\)
So, we have to add them up and simplify the equation made.
\(n+n+2+n+4+n+6=244 \\ 4n+12=244 \\ 4n+(12-12)=(244-12) \\ 4n=232 \\ \frac{4n}{4}= \frac{232}{4} \\ n=58\)
So, you just substitute 58 into the numbers
\(n=58 \\ n+2=58+2=60 \\ n+4=58+4=62 \\ n+6=58+6=64\)
The four consecutive even integers are 58, 60, 62 and 64.