we have
Yellow paint
\(1\frac{1}{3} =(3*1+1)/3\\ \\ =\frac{4}{3} gal\)
Find the
amount of yellow paint left after painting the mural
\((\frac{4}{3} -\frac{3}{4} )=(4*4-3*3)/12\\ \\ =\frac{7}{12} gal\)
Green paint
\(1\frac{1}{4} =(4*1+1)/4\\ \\ =\frac{5}{4} gal\)
Find the
amount of green paint left after painting the mural
\((\frac{5}{4} -\frac{3}{4} )=(5-3)/4\\ \\ =\frac{2}{4} gal\)
Blue paint
\(\frac{7}{8}gal\)
Find the
amount of blue paint left after painting the mural
\((\frac{7}{8} -\frac{3}{4} )=(7-2*3)/8\\ \\ =\frac{1}{8} gal\)
Find the
total amount of paint left after painting the mural
\(\frac{7}{12} +\frac{2}{4} +\frac{1}{8} =\frac{(2*7+6*2+3*1)}{24} \\ \\ =\frac{29}{24} gal\)
\(\frac{29}{24} =1\frac{5}{24} gal\)
therefore
the answer is
\(1\frac{5}{24} gal\)
