A tennis coach took his team out for lunch and bought 8 hamburgers and 5 fries for $24. The players were still hungry so the coach bought 6 more hamburgers and 2 more fries for $16.60. Find the cost of each.
Basically this is a systems of equations question. We set up two equations, X is hamburgers Y is fries
8x + 5y = 24
6x + 2y = 16.60
then you solve for each to get your answer.
Answer : The cost of hamburgers and fries is, $2.5 and $0.8
Step-by-step explanation :
Let the cost of hamburgers be, x and the cost of fries be, y.
Thus the two equation will be:
\(8x+5y=24\) ...........(1)
\(6x+2y=16.60\) .............(2)
Using substitution method:
From equation 1 we have to determine the value of 'y'.
\(8x+5y=24\)
\(5y=24-8x\)
\(y=\frac{24-8x}{5}\) ........(3)
Now put equation 3 in 2, we get:
\(6x+2y=16.60\)
\(6x+2\times (\frac{24-8x}{5})=16.60\)
\(6x+(\frac{48-16x}{5})=16.60\)
\(\frac{30x+48-16x}{5}=16.60\)
\(30x+48-16x=83\)
\(14x=35\)
\(x=2.5\)
Now put the value of x in equation 3, we get:
\(y=\frac{24-8x}{5}\)
\(y=\frac{24-8\times 2.5}{5}\)
\(y=\frac{24-20}{5}\)
\(y=\frac{4}{5}\)
\(y=0.8\)
Thus, the cost of hamburgers and fries is, $2.5 and $0.8