Answer: The change velocity of the tight end is 4.44 m/s
Explanation:
Mass of the tight end = 90 kg
Initial velocity =\(u\) = 9.0 m/s
Final velocity =\(v\)
\(Impulse=Force\times Time\)
\(Impulse=Mass \times acceleration\times Time\)
\(a=\frac{dv}{dt}=\frac{[v-u]}{t}\)
\(impulse=Mass \times [v-u]\)
\(400 Nm=90 kg\times[v-9.0 m/s]\)
\(v=13.44 m/s\)
Change in velocity = 13.44 m/s - 9m/s = 4.44 m/s
The change velocity of the tight end is 4.44 m/s
