how to factor 64x^4 + xy^3
you factor out an x and getx(64x^3+y^3)
so we kkonw that 64=4^3 so if we factor out x we getx(4^3(x^3)+y^3) or x[(4x)^3+y^3)so the additon of two perfect cubes so(4x+y)(16x^2+4xy+y^2)and we remember that this is all times x so x[(4x+y(16^2+4xy+y^2))] or (x)(4x+y)(16x^2+4xy+y^2)