Verified Answer :

DMBZarate


5(x+(x+1)+(x+2))=150

5(3x+3)=150

15x+15=150

15x=135

x=9

Your three consecutive integers are 9, 10, and 11.

tylolsmart

Let x=1st integer 
x+1=2nd integer 
x+2=3rd integer 

5(x+x+1+x+2)=150 
5(3x+3)=150 
15x+15=150 
15x=135 
x=9 

So you put what x is 
1st integer (x)= 9 
Since it's three consecutive integers, you add one to the 2nd integer 
2nd integer (x+1)= 10 
Then you do the same thing for the third integer 
3rd integer (x+2)= 11

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