\(3a^2+4=2a\\
3a^2-2a+4=0\\
\Delta=(-2)^2-4\cdot3\cdot4=4-48=-44\\
\sqrt{\Delta}=\sqrt{-44}=2\sqrt{11}i\\
x_1=\frac{-(-2)-2\sqrt{11}i}{2\cdot3}=\frac{2-2\sqrt{11}i}{6}=\frac{1-\sqrt{11}i}{3}\\
x_2=\frac{-(-2)+2\sqrt{11}i}{2\cdot3}=\frac{2+2\sqrt{11}i}{6}=\frac{1+\sqrt{11}i}{3}\\\)
