The fountain contains 20 pennies and 9 dimes. A coin is randomly taken and not replaced. A second coin is randomly taken. What is the probability that both coins are pennies?
Well, the first coin has chance \(\frac{20}{29}\) to be a penny. When it is a penny, the only valid case (the other case gives 0 for the multiplications later, so it is ignored) gives \(\frac{19}{28}\) chance for the second one to be a penny. The result is \(\frac{20*19}{29*28}\), which is \(\frac{95}{203}\), or about 46.80% (rounded to the first 2 decimals)
Answer:
9 dimes
Step-by-step explanation:
th fountai contains more that wat u would think but u mist move