\(x-2y=6\\
-2y=-x+6\\
y=\frac{1}{2}x-3\\\\equation\ of\ line\ parallel\ to \given \one
\\\\y=ax+b\\\\
If\ line\ is\ parallel\ a=\frac{1}{2}\\\\y=\frac{1}{2}x+b\\\\
Substituting\ point\ (-2,4)\\\\
4=-2*\frac{1}{2}+b\\4=-1+b\\b=5\\\\
Equation\ of\ line\ y=\frac{1}{2}x+5\\\\
Standard form:\\ -\frac{1}{2}x+y=5\)
