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A quadratic equation of the form 0 = ax2 + bx + c has a discriminant value of –16. How many real number solutions does the equation have? help me please

Verified Answer :

superkoopasirf

The discriminant of a quadratic is given as \(b^2 - 4ac\), so we know that \(b^2 - 4ac = -16.\)

When using the quadratic formula to calculate values for \(x\), we have to take the root of the discriminant. There is no real answer to the root of a negative number and so the equation has no real roots.

Answer:

A given quadratic equation has no real roots.

Step-by-step explanation:

Given a quadratic equation of the form \(ax^2+bx+c=0\) has a discriminant value of –16. we have to find number of real solutions the equation have.

As given discriminant is -16

The formula to find the roots of quadratic equation by discriminant rule is

\(x=\frac{-b\pm\sqrt D}{2a}\), \(\text{where D is discriminant}\)

\(x=\frac{-b\pm\sqrt{-16}}{2a}\)

\(x=\frac{-b\pm4i}{2a}\)

which shows that neither of the solutions are real numbers.

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