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umar190 umar190
  • 17-11-2014
  • Mathematics
Answered

Having a bit trouble with this. Can some one please help? Thanks

Having a bit trouble with this. Can some one please help? Thanks class=

Verified Answer :

superkoopasirf
superkoopasirf superkoopasirf
  • 17-11-2014

\(2 - \sqrt{-4} - 3 + \sqrt{-16}\)
\(= 2 - i\sqrt{4} - 3 + i\sqrt{16}\)
\(= 2 - 2i - 3 + 4i\)
\(= -1 + 2i\)

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AL2006
AL2006 AL2006
  • 17-11-2014

The square root of (-4) = square root of  (-1) x (4) = 2i

The square root of (-16) = square root of (-1) x (16) = 4i

So now you have the sum of  (2 - 2i) and (-3 + 4i).

The real part of the sum is (2 - 3) = -1

The imaginary part of the sum is ( -2i + 4i ) = +2i

The whole sum is    -1 + 2i .

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