Having a bit trouble with this. Can some one please help? Thanks
Having a bit trouble with this. Can some one please help? Thanks
\(2 - \sqrt{-4} - 3 + \sqrt{-16}\)
\(= 2 - i\sqrt{4} - 3 + i\sqrt{16}\)
\(= 2 - 2i - 3 + 4i\)
\(= -1 + 2i\)
The square root of (-4) = square root of (-1) x (4) = 2i
The square root of (-16) = square root of (-1) x (16) = 4i
So now you have the sum of (2 - 2i) and (-3 + 4i).
The real part of the sum is (2 - 3) = -1
The imaginary part of the sum is ( -2i + 4i ) = +2i
The whole sum is -1 + 2i .