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Evelinmore Evelinmore
  • 16-11-2014
  • Mathematics
Answered

Help me, please!! Estoy desesperada y no hablo inglês!! Help

Help me, please!! Estoy desesperada y no hablo inglês!! Help class=

Verified Answer :

konrad509
konrad509 konrad509
  • 16-11-2014

\(D:x>0\\ \log x+\log x^2+\log x^3=-6\\ \log (x\cdot x^2\cdot x^3)=\log 10^{-6}\\ x^6=10^{-6}\\ x^6=\left(\frac{1}{10}\right)^6\\ \boxed{x=\frac{1}{10}}\)

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FirstSineOfMadness
FirstSineOfMadness FirstSineOfMadness
  • 16-11-2014

Log x^n = nLog x
log x + log x^2 + log x^3
Log x + 2 log x +3 log x = -6
6 log x = -6
Log x = -1
X=10^-1 = 1/10
Respuesta final
X=1/10

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