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Could someone help please?

The Sales S (in thousands of units) of a cleaning solution after X hundred dollars is spent on advertising are given:

S = 10(1 - e^(kx))

Now when $325 is spent on advertising 2300 units are sold.


(a)Complete by solving for k. (Round your answer to 4 decimal places)

k = _______

BWhat number of units that will be sold if advertising is raised up to $425

_______ Units.

Verified Answer :

konrad509

\(2.3=10(1-e^{3.25k}))\\ 2.3=10-10e^{3.25k}\\ 10e^{3.25k}=7.7\\ e^{3.25k}=0.77\\ 3.25k=\ln 0.77\\ k=\frac{\ln 0.77}{3.25}\\ k\approx-0.0804\)

\(S=10(1-e^{\frac{\ln 0.77}{3.25}\cdot4.25})\\\)

Calculating this is a pain in the ***, but as a result you get approximately 2.8949 which in thousands of units is 2894 (rounded down since you can't have a fraction of a unit).

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