tony05
Answered

A container has 50 electronic components, of which 10 are defective.

If 8 components are drawn at random from the container, what is the probability that exactly 3 of them are defective?

Verified Answer :

Coding8with8Valor

(10/50) (3/8) = .075
.075 100 = 7.5% chance of this happening

Answer:

\(0.1468 \\= 0.147\)

Step-by-step explanation:

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