Verified Answer :

The answer is . . . 786.8 N (see work attached)

normal force = (mg)cos(θ) = (82kg)(9.81 m/s²)cos(12⁰) = 786.8 N

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Normal force on an incline is \(N=m * g * cos(x)\) Where \(m = 82kg\) and \(g = 9.8 m/s2\)

Therefore:

\(N=82 * 9.8 * cos(12)\)
\(N=803.6 * cos(12)\)
\(N=803.6 * .98\)
\(N=787.528\)

Normal force is 787.528 N.

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