Answer:
\(\sin(90^{\circ} - x)=\frac{1}{3}\)
Step-by-step explanation:
Given: \(\cos (x)=\frac{1}{3}\)
We have to find the value of \(\sin(90^{\circ} - x)\)
Since Given \(\cos (x)=\frac{1}{3}\)
Using trigonometric identity,
\(\sin(90^{\circ} - \theta)=\cos\theta\)
Thus, for \(\sin(90^{\circ} - x)\) comparing , we have,
\(\theta=x\)
We get,
\(\sin(90^{\circ} - x)=\cos x=\frac{1}{3}\)
Thus, \(\sin(90^{\circ} - x)=\frac{1}{3}\)
