jadiesilva
Answered

Joaquin has created a small treasure map that is in the shape of a square. He decides to make a larger version of the map, and on this new map he increases each side by 6 inches. The area of this larger version of the map is 121 square inches. What are the dimensions of his original, smaller map?

Verified Answer :

(l+6)(l+6)=121=l^2+6l+6l+36
l^2+12l-85=(l-5)(l+17)
l=5 or l =-17 
cannot be negative
therefore was a 5 by 5 map


Limosa

Answer:

The length of a side of the smaller map is 5 inches.

Step-by-step explanation:

Lets take the original length of a side of the Map is \(x\) inches.

So the length of a side if the new Map = \(x+6\) inches.

Area of a square = (Length of a side)²

\(121=(x+6)^{2}\)

\(\sqrt{121} =\sqrt{(x+6)^{2}  }\)

So, either

\(11=x+6\)              or             \(-11=x+6\)

\(5=x\)                   or            \(-17=x\)

\(x\) cannot be a negative value as it is a length of a square.

Therefore. the length of a side of the smaller map is 5 inches.


Related Questions