hallie has 10 times as many pages to read for her homework assignment as janet, altogether , they have to read 264 pages. how many pages does each girl have to read
Let \(j\) be the number of pages Janet has to read.
so Hallie has \(10j\) pages to read.
Altogether, they must read \(10j + j\) pages, which is \(11j\). So this means that \(11j\) must be equal to \(264\).
If you divide both bits by \(11\), you get \(j = \frac{264}{11} = 24\).
So, Janet has to read \(j\) pages, which is \(24\), and Hallie has to read \(10j\) pages, which is \(240\).
they read all together you divide then the quotient you divide it by 10 that's how u get ur answer13.2